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Mathematics solution NCERT

Class 9 - Chapter 3: The World of Numbers

NCERTChapter 3Solution- Exercise Set 3.3

Q1: Prove that the following rational numbers are equal.

(i) 2/3 and 4/6

4/6 = (4 ÷ 2)/(6 ÷ 2)

= 2/3

Therefore,

2/3 = 4/6


(ii) 5/4 and 10/8

10/8 = (10 ÷ 2)/(8 ÷ 2)

= 5/4

Therefore,

5/4 = 10/8


(iii) -3/5 and -6/10

-6/10 = (-6 ÷ 2)/(10 ÷ 2)

= -3/5

Therefore,

-3/5 = -6/10


(iv) 9/3 and 3

9/3 = 3

Therefore,

9/3 = 3


Q2: Find the Sum

(i) 2/5 + 3/10

LCM of 5 and 10 = 10

2/5 = 4/10

4/10 + 3/10 = 7/10

Answer: 7/10


(ii) 7/12 + 5/8

LCM of 12 and 8 = 24

7/12 = 14/24

5/8 = 15/24

14/24 + 15/24 = 29/24

Answer: 29/24


(iii) -4/7 + 3/14

LCM of 7 and 14 = 14

-4/7 = -8/14

-8/14 + 3/14 = -5/14

Answer: -5/14


Q3: Find the Difference

(i) 5/6 - 1/4

LCM of 6 and 4 = 12

5/6 = 10/12

1/4 = 3/12

10/12 - 3/12 = 7/12

Answer: 7/12


(ii) 11/8 - 3/4

3/4 = 6/8

11/8 - 6/8 = 5/8

Answer: 5/8


(iii) -7/9 - (-2/3)

= -7/9 + 2/3

= -7/9 + 6/9

= -1/9

Answer: -1/9


Q4: Find the Product

(i) 2/3 × 3/10

(2 × 3)/(3 × 10)

= 6/30

= 1/5

Answer: 1/5


(ii) 7/11 × 5/8

(7 × 5)/(11 × 8)

= 35/88

Answer: 35/88


(iii) -4/7 × 5/14

(-4 × 5)/(7 × 14)

= -20/98

= -10/49

Answer: -10/49


Q5: Find the Quotient

(i) 2/3 ÷ 3/10

2/3 × 10/3

= 20/9

Answer: 20/9


(ii) 7/11 ÷ 5/8

7/11 × 8/5

= 56/55

Answer: 56/55


(iii) -4/7 ÷ 5/14

-4/7 × 14/5

= -56/35

= -8/5

Answer: -8/5


Q6: Show that (1/2 + 3/4) × 8/3 = (1/2 × 8/3) + (3/4 × 8/3)

LHS:

(1/2 + 3/4) × 8/3

= (2/4 + 3/4) × 8/3

= 5/4 × 8/3

= 10/3


RHS:

(1/2 × 8/3) + (3/4 × 8/3)

= 4/3 + 2

= 4/3 + 6/3

= 10/3


LHS = RHS

Hence Proved.


Q7: Simplify using the distributive property

7/9 (6/7 - 3/4)

Using distributive property:

= (7/9 × 6/7) - (7/9 × 3/4)

= 6/9 - 21/36

= 2/3 - 7/12

= 8/12 - 7/12

= 1/12

Answer: 1/12


Q8: Find the rational number x such that:

(5/6)(x + 3/5) = (5/6)x + 1/2

Solution:

Expand the left side:

(5/6)x + (5/6 × 3/5)

(5/6)x + 1/2

The equation becomes:

(5/6)x + 1/2 = (5/6)x + 1/2

Both sides are identical.

This means the equation is true for every value of x.

Answer: Any rational number can be the value of x.

Hence, x can be any rational number.