Mathematics solution NCERT
Class 10 - Chapter 2: Polynomials
Question 1
Find the zeroes of the following quadratic polynomials and verify the relationship between the zeroes and the coefficients.
NOTE: For a quadratic polynomial: the standard form is = ax2 + bx + c:
Sum of zeroes(α + β) = −b/a
Product of zeroes(αβ) = c/a
(Important for board exams)
(i) x2 − 2x − 8
x2 − 2x − 8
By doing the middle term split, we get
x2 − 4x + 2x − 8
= (x − 4)(x + 2)
Put (x - 4) = 0
x - 4 = 0
x = 4
Now Put (x + 2) = 0
x + 2 = 0
x = -2
Zeroes = 4, −2
Sum of zeroes(α + β) = 4 + (−2) = 2
−b/a = −(−2)/1 = 2
Product of zeroes(αβ) = 4 × (−2) = −8
c/a = −8/1 = −8
(ii) 4s2 − 4s + 1
4s2 − 4s + 1 = (2s − 1)2
Zeroes = 1/2, 1/2
Sum of zeroes(α + β) = 1/2 + 1/2 = 1
−b/a = −(−4)/4 = 1
Product of zeroes(αβ) = (1/2)(1/2) = 1/4
c/a = 1/4
(iii) 6x2 − 3 − 7x
Rearrange:
6x2 − 7x − 3
= 6x2 − 9x + 2x − 3
= 3x(2x − 3) + 1(2x − 3)
= (3x + 1)(2x − 3)
Zeroes = −1/3, 3/2
Sum of zeroes(α + β) = −1/3 + 3/2
= (−2 + 9)/6
= 7/6
−b/a = −(−7)/6 = 7/6
Product of zeroes(αβ) = (−1/3)(3/2) = −1/2
c/a = −3/6 = −1/2
(iv) 4u2 + 8u
4u(u + 2) = 0
Zeroes = 0, −2
Sum of zeroes(α + β) = 0 + (−2) = −2
−b/a = −8/4 = −2
Product of zeroes(αβ) = 0 × (−2) = 0
c/a = 0/4 = 0
(v) t2 − 15
t2 − 15 = 0
t = ±√15
Zeroes = √15, −√15
Sum of zeroes(α + β) = √15 − √15 = 0
−b/a = 0 ✓
Product of zeroes(αβ) = (√15)(−√15)
= −15
c/a = −15
(vi) 3x2 − x − 4
3x2 − x − 4
= 3x2 − 4x + 3x − 4
= x(3x − 4) + 1(3x − 4)
= (x + 1)(3x − 4)
Zeroes = −1, 4/3
Sum of zeroes(α + β) = −1 + 4/3
= 1/3
−b/a = −(−1)/3 = 1/3
Product of zeroes(αβ) = (−1)(4/3)
= −4/3
c/a = −4/3
Question 2
Find a quadratic polynomial whose zeroes are the given numbers.
If the zeroes of a polynomial are α and β, then Polynomial = x2 − (α + β)x + αβ
(i) Zeroes = 1/4, −1
Sum(α + β) = 1/4 − 1 = −3/4
Product(αβ) = −1/4
Polynomial:
x2 + (3/4)x − 1/4
Multiplying by 4:
4x2 + 3x − 1
(ii) Zeroes = √2, 1/3
Sum (α + β)= √2 + 1/3
Product (αβ)= √2/3
Polynomial:
x2 − (√2 + 1/3)x + √2/3
Multiplying by 3:
3x2 − (3√2 + 1)x + √2
(iii) Zeroes = 0, √5
Sum(α + β) = √5
Product(αβ) = 0
Polynomial:
x2 − √5x
x(x − √5)
(iv) Zeroes = 1, 1
Sum(α + β) = 2
Product(αβ) = 1
Polynomial:
x2 − 2x + 1
(x − 1)2
(v) Zeroes = −1/4, 1/4
Sum (α + β)= 0
Product (αβ)= −1/16
Polynomial:
x2 − 1/16
Multiplying by 16:
16x2 − 1
(vi) Zeroes = 4, 1
Sum(α + β) = 5
Product(αβ) = 4
Polynomial:
x2 − 5x + 4
Is chapter me se almost Sum(α + β) and Product(αβ) se hi jyada questions puche jate hain.
Number of questions bahut type ke ban sakte hain to jyada practice karo ese questions ki.